正则匹配

qingchenggua

<a class="product_title_txt" > </a> <div class="p-l-pages-timebox-box"> <p class="media-heading"> aaaaaaaabbbbbbbbbbbbbbbbbbbbbbbbbaaaa111</p> </a> <span class="pro-list-view-all" style="display: none">View All</span> <ul class="attribute"> <span class="danjia">1.2</span> <a class="product_title_txt" > </a> <div class="p-l-pages-timebox-box"> <p class="media-heading"> bbbbbbbbbaaaaaaaaaaaaaaaaaabbbbbbbbb333 </p> </a> <span class="pro-list-view-all" style="display: none">View All</span> <ul class="attribute"> <span class="danjia">1.0</span> 想匹配出来aaaaaaaabbbbbbbbbbbbbbbbbbbbbbbbbaaaa111----1.2和bbbbbbbbbaaaaaaaaaaaaaaaaaabbbbbbbbb333----1.0 不知道里面的多行文本用哪个表示 还要匹配出1.2和1.0  尽量有更通用的匹配符号 类似 <p class="media-heading">匹配符号</p>匹配符号danjia匹配符号</span>   不知道能不能行

StarAdmire

<span class="danjia">(.*?)</span>

StarAdmire

<(p|span) class="(media-heading|danjia)"> (.*?)</(p|span)>

补充内容 (2023-7-4 20:07):
用这个都可以取到

蛀牙

([\w\s]+)</p>[\S\s]+?danjia">(.+?)</span>

dingli123

r'\baaaaaaaaabbbbbbbbbbbbbbbbbbbbbbbaaaa111(?:----(\d+\.\d+))?\b|bbbbbbbbbaaaaaaaaaaaaaaaaaabbbbbbbbb333(?:----(\d+\.\d+))?\b'

dingli123

dingli123 发表于 2023-7-4 20:28
r'\baaaaaaaaabbbbbbbbbbbbbbbbbbbbbbbaaaa111(?:----(\d+\.\d+))?\b|bbbbbbbbbaaaaaaaaaaaaaaaaaabbbbbbbb ...

r'<p class="media-heading">.*?<\/p><span class="danjia">(\d+\.\d+)'是这个

afu45

ding.*\s+(.*?)</p[\w\W]*?>(\d+\.\d+)</s

时髦猪

[JavaScript] 纯文本查看 复制代码

<p class="media-heading">(.*?)</p>(.*?)<span class="danjia">(.*?)</span>

这样对么
用子匹配文本1和3

w589321

正则表达式：<p class="media-heading">([\s\S]*?)</p>[\w\W]*?<span class="danjia">(.*?)</span>

涂学刑正

[a-b]+\d{3}|[120.]{3}