有什么高效的办法可以检测坐标点形成的直线

ssoyee

.版本 2

            x={76,77,74,75,76,77,73,74,75,76,77,73,74,73,74,73,74,75,74,75,74,75,74,75,76,77,72,75,76,77,75,76,75,76,75,76,77,76,77,76,77,76,77,77,77,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,77,77,76,77,75,76,75,76,74,75,73,74,73,74,72,73,71,72,70,71,72,70,71,69,70,68,69,70,68,69,67,68,66,67,68,66,67,65,66,64,65,64,65,63,64,62,63,62,61,62,60,61,60,61,59,60,58,59,57,58,59,57,58,56,57,55,56,57,55,56}
            y={4,4,64,64,64,64,65,65,65,65,65,66,66,67,67,68,68,68,69,69,70,70,71,71,71,71,72,72,72,72,73,73,74,74,75,75,75,76,76,77,77,78,78,79,80,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,82,83,83,84,84,85,85,86,86,87,87,88,88,89,89,90,90,91,91,91,92,92,93,93,94,94,94,95,95,96,96,97,97,97,98,98,99,99,100,100,101,101,102,102,103,103,104,105,105,106,106,107,107,108,108,109,109,110,110,110,111,111,112,112,113,113,113,114,114}

这是一条20个像素以上的180度的直线和一条60度的直线，还有一些20个像素以下的直线，怎么用算法高效获取到20个像素以上的直线的坐标组，AI问的效果不太行

笨来无一悟

76-4一组 77-4一组 74-64一组 75-64一组 这个意思? 弄到自定义的坐标型里面?

ssoyee

笨来无一悟 发表于 2025-4-12 22:41
76-4一组 77-4一组 74-64一组 75-64一组 这个意思? 弄到自定义的坐标型里面?

直线x{77,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67}

直线Y:{79,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81,81}  这样就是取到其中一条直线

ssoyee

ssoyee 发表于 2025-4-12 23:23
直线x{77,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50 ...

这个图是上面那一堆坐标生成的，我要取出红框两条直线的坐标组，AI的回答是套3层循环计算两点之间的距离为1则在同一条直线上