IMAP收取的邮件如何解码解析。

W先生丿 · 发表于 2024-4-13 18:02:41

看了一天的编码解码，找到个Quoted-printable这个解码。但是没有一个好用的，比如这封邮件，我就只想简单的取主题，取发件人，取内容请问下怎么搞。。

on-Id: bb7c5b78-ebc1-4d22-7646-08dbd06b15aa
X-MS-Exchange-EOPDirect: true
X-Sender-IP: 66.220.155.158
X-SID-PRA: NO-REPLY@MAIL.INSTAGRAM.COM
X-SID-Result: PASS
X-MS-Exchange-Organization-PCL: 2
X-MS-Exchange-Organization-SCL: 1
X-Microsoft-Antispam: BCL:1;
X-MS-Exchange-CrossTenant-OriginalArrivalTime: 19 Oct 2023 06:17:34.2096
(UTC)
X-MS-Exchange-CrossTenant-Network-Message-Id: bb7c5b78-ebc1-4d22-7646-08dbd06b15aa
X-MS-Exchange-CrossTenant-Id: 84df9e7f-e9f6-40af-b435-aaaaaaaaaaaa
X-MS-Exchange-CrossTenant-AuthSource:
VI1EUR03FT003.eop-EUR03.prod.protection.outlook.com
X-MS-Exchange-CrossTenant-AuthAs: Anonymous
X-MS-Exchange-CrossTenant-FromEntityHeader: Internet
X-MS-Exchange-CrossTenant-RMS-PersistedConsumerOrg:
00000000-0000-0000-0000-000000000000
X-MS-Exchange-Transport-CrossTenantHeadersStamped: SN4PR10MB5800
X-MS-Exchange-Transport-EndToEndLatency: 00:00:03.1758613
X-MS-Exchange-Processed-By-BccFoldering: 15.20.6886.034
X-Microsoft-Antispam-Mailbox-Delivery:
ucf:0;jmr:0;ex:0;auth:1;dest:I;ENG:(5062000305)(920221119095)(90000117)(920221120095)(90010023)(91010020)(91040095)(9050020)(9100341)(944500132)(4810010)(4910033)(9910022)(9510006)(10110021)(9320005)(120001);
X-Message-Info:
qZelhIiYnPn9AAVU/5994M+FVnHctwIs+fm1oEJfKT6/xJ0WbTr+PceVGehl6irB8V8F5Kb0o/k/DY3d2bNcdfBC8haRfJLVYjnNXZvK4yTKE0DqXy8JxPq70Qj87RH2XWfAYZQdi1Id+G4rbNVIVYaLhZEdVwfyhiVu077EzznR/VcHTEWLeCFPjTolp7/INCHFqPuCG/SKO/nUO06VDA==
X-Message-Delivery: Vj0xLjE7dXM9MDtsPTA7YT0xO0Q9MTtHRD0xO1NDTD0tMQ==
X-Microsoft-Antispam-Message-Info:
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MIME-Version: 1.0

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FLAGS (\Seen))

W先生丿 · 发表于 2024-4-14 02:10:48

没人解决啊。。。我都已经研究出来了。。。。把=号和换行符替换成%再URL解码就能取出内容不乱码了。

申请撤消悬赏了， @大司命

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[求助] IMAP收取的邮件如何解码解析。