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楼主 |
发表于 2023-5-28 02:47:06
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美国
也确实,叫他计算个东西还能出错
how to calculate the amount of moles of 94.2g MgO2
To calculate the amount of moles of 94.2g MgO2, you can use the following formula:
Code snippet
moles = mass / molar mass
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The mass of MgO2 is 94.2g and the molar mass of MgO2 is 40.31 g/mol. Therefore, the number of moles of MgO2 is:
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moles = 94.2g / 40.31 g/mol = 2.34 moles
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Therefore, there are 2.34 moles of MgO2 in 94.2g of MgO2.
Here are the steps in detail:
Write the balanced chemical equation. The balanced chemical equation for the reaction between Mg and O2 is:
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2Mg + O2 → 2MgO
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Determine the molar mass of MgO2. The molar mass of MgO2 is 40.31 g/mol.
Use the molar ratio from the balanced equation to convert moles of Mg to moles of MgO2. The molar ratio of Mg to MgO2 is 2:2. This means that for every 2 moles of Mg, there are 2 moles of MgO2.
Calculate the number of moles of MgO2. To calculate the number of moles of MgO2, we can use the following formula:
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moles of MgO2 = moles of Mg * molar ratio of Mg to MgO2
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Substituting the values, we get:
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moles of MgO2 = 2.34 moles * 2 = 4.68 moles
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Therefore, there are 4.68 moles of MgO2 in 94.2g of MgO2.
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