POST提交是乱码，这个编码是什么

guoduopopo

POST提交是乱码，这个编码是什么

post提交的数据：kfguin=938028721&ext=1001&ql=2212366654;&g=鎴戜富鍔ㄥ姞鐨?msg=88888888888888&v=aymx&

上面这个编码应该转化成什么，谢谢

抓包数据：

POST /cgi/aq?t=8994385885496064 HTTP/1.1
Accept: */*
Accept-Language: zh-cn
Referer: http://bizapp.qq.com/home.htm#t5u1s1
Content-Type: text/plain; charset=utf-8
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; qdesk 2.3.1186.202; .NET CLR 2.0.50727)
Host: bizapp.qq.com
Content-Length: 85
Connection: Keep-Alive
Cache-Control: no-cache
Cookie: verifysession=h0085e9d037f23f59930de01fea0276f5f288ed4aa723d83106dc419e48ab8a76c9ac06fa287af6fc9b; _gscbrs_661903259=1; pgv_info=ssid=s6440686222; bizt_name=%E5%AE%9D%E5%84%BF%E5%A4%96%E8%B4%B8; bizt_ext=1001; bizt_uin=938028721; _gscu_661903259=59607451xwzviu12; _gscs_661903259=5960745136wuwv12|pv:3; pgv_pvid=430908455; pgv_pvi=8350003200; pt2gguin=o2212366654; RK=x1DO52JOfF; ptui_loginuin=624536955; __hash__=ab1879fd4515b8193af2b70084e161a7; o_cookie=2212366654; uin_cookie=2212366654; euin_cookie=E24EFF30C55040F3D547D6518D96E503A4BF8F7364FE17A4; ac=1,016,004; deltatime=1359609161753; vil_et=1577808000; kffs=343; kfdj=2; kfmc=5221; kfwl=1; kfcookie=kfskey:34C9654BF2DB162A4106AE5A2BAA3DD971784B37323A7179484CD7BA4ACCDD7C$kfguin:938028721$ext:1001; kfuin=938028721; kfext=1001; showsp=1; showvas=9; pflag=0; kfwebnotify=1002; kfgoodv=6; kfbadv=0
kfguin=938028721&ext=1001&ql=2212366654;&g=鎴戜富鍔ㄥ姞鐨?msg=88888888888888&v=aymx&

特思软件

URL编码码UTF8

冰点

utf8转gb2312 呢，。用助手的 一键转码 你可以试试