|
发表于 2023-9-18 13:43:53
|
显示全部楼层
广西壮族自治区崇左市
function nvalue(e, t) {
for (var a = 0; a < t.length - 2; a += 3) {
var o = t.charAt(a + 2);
o = o >= "a" ? o.charCodeAt(0) - 87 : Number(o),
o = "+" === t.charAt(a + 1) ? e >>> o : e << o,
e = "+" === t.charAt(a) ? e + o & 4294967295 : e ^ o
}
return e
}
function value(e) {
var t = "320305.131321201"
, o = e.match(/[\uD800-\uDBFF][\uDC00-\uDFFF]/g);
if (null === o) {
var i = e.length;
i > 30 && (e = "" + e.substr(0, 10) + e.substr(Math.floor(i / 2) - 5, 10) + e.substr(-10, 10))
} else {
for (var n = e.split(/[\uD800-\uDBFF][\uDC00-\uDFFF]/), r = 0, s = n.length, c = []; s > r; r++)
"" !== n[r] && c.push.apply(c, a(n[r].split(""))),
r !== s - 1 && c.push(o[r]);
var l = c.length;
l > 30 && (e = c.slice(0, 10).join("") + c.slice(Math.floor(l / 2) - 5, Math.floor(l / 2) + 5).join("") + c.slice(-10).join(""))
}
var u = void 0
, d = "" + String.fromCharCode(103) + String.fromCharCode(116) + String.fromCharCode(107);
u = null !== t ? t : (t = window[d] || "") || "";
for (var f = u.split("."), g = Number(f[0]) || 0, p = Number(f[1]) || 0, v = [], m = 0, b = 0; b < e.length; b++) {
var h = e.charCodeAt(b);
128 > h ? v[m++] = h : (2048 > h ? v[m++] = h >> 6 | 192 : (55296 === (64512 & h) && b + 1 < e.length && 56320 === (64512 & e.charCodeAt(b + 1)) ? (h = 65536 + ((1023 & h) << 10) + (1023 & e.charCodeAt(++b)),
v[m++] = h >> 18 | 240,
v[m++] = h >> 12 & 63 | 128) : v[m++] = h >> 12 | 224,
v[m++] = h >> 6 & 63 | 128),
v[m++] = 63 & h | 128)
}
for (var w = g, A = "" + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(97) + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(54), k = "" + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(51) + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(98) + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(102), x = 0; x < v.length; x++)
w += v[x],
w = nvalue(w, A);
return w = nvalue(w, k),
w ^= p,
0 > w && (w = 2147483648 + (2147483647 & w)),
w %= 1e6,
w.toString() + "." + (w ^ g)
}
补充内容 (2023-9-18 14:27):
执行value('你请求载荷的params内容') |
评分
-
查看全部评分
|