提取json的 nick，用精易模块里的类

1712385842

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V雪落有声V

首先要根据这个网站的解析结果来分清层次关系：http://www.bejson.com/jsonviewernew/
方法，将整个的JSON粘贴，然后点击视图。就可以得到清晰的视图。
随后根据结构关系，调用如下命令：

子Json_result ＝ JSON解析.取属性 (“result.buddy.info_list”)

这时候"子Json_result"中保存的就是info_list中所有的成员。
再接下来就可以通过一个循环来获取每一个成员中的数值了。 具体请看附件。
解决问题.rar (535.81 KB, 下载次数: 25)

2015-11-7 20:02 上传

点击文件名下载附件

ovo555

正则：   nick" : "(.*?)"

剩下我de孩子气

永正则或者披露取中间内容啊

1712385842

ovo555 发表于 2015-11-5 22:43
正则：   nick" : "(.*?)"

json，格式提取，正则我会