arg7={ “0”, “1”, “2”, “3”, “4”, “5”, “6”, “7”, “8”, “9”, “A”, “B”, “C”, “D”, “E”, “F” }
------------------------------
protected static char[] a(byte[] arg6, char[] arg7) {
int v0 = 0;
int v2 = arg6.length;
char[] v3 = new char[v2 << 1];
int v1;
for(v1 = 0; v1 < v2; ++v1) {
int v4 = v0 + 1;
v3[v0] = arg7[(arg6[v1] & 240) >>> 4];
v0 = v4 + 1;
v3[v4] = arg7[arg6[v1] & 15];
}
return v3;
}
}
自己有尝试着弄出来都不是结果,求告知!!
----------------------------------------下面是我自己理解的,写出来的结果不对。
.版本 2
.支持库 spec
v5 = { “0”, “1”, “2”, “3”, “4”, “5”, “6”, “7”, “8”, “9”, “A”, “B”, “C”, “D”, “E”, “F” }
v0 = 1
v2 = 取字节集长度 (参数一)
调试输出 (v2)
' 重定义数组 (v3, 假, 左移 (v2, 1))
v3 = { 52, 57, 55, 52, 49, 52, 70, 67, 51, 54, 53, 56, 69, 57, 55, 49, 54, 50, 52, 69, 69, 52, 52, 48, 70, 69, 53, 48, 48, 68, 57, 52, 52, 57, 55, 52, 49, 52, 70, 67, 51, 54, 53, 56, 69, 57, 55, 49, 54, 50, 52, 69, 69, 52, 52, 48, 70, 69, 53, 48, 48, 68, 57, 52 }
' 调试输出 (v2)
' 调试输出 (参数一 [16])
' v3 = { } + { 0, 1, 2 }
' v3 = 左移 (v2, 1)
' 调试输出 (到字节集 (v5 [16]))
.判断循环首 (v1 < v2)
v1 = v1 + 1
' b = 到字节 (十六到十 (v5 [到整数 (右移 (位与 (参数一 [v1], 240), 4)) + 1]))
c = 十到二 (v5 [到整数 (右移 (位与 (参数一 [v1], 240), 4)) + 1])
v3 [v0] = c
v4 = v0 + 1
调试输出 (c, v3 [v0])
' v3[v0] = V5[(参数一[v1] & 240) >>> 4]
v0 = v4 + 1
c = 到整数 (位与 (参数一 [v1], 15) + 1)
' b = 到字节 (十六到十 (v5 [c]))
v3 [v4] = 十到二 (v5 [c])
.判断循环尾 ()
|